OSSC JEO & JA Answer Key 2024 Out, Response Sheet Link


Odisha Staff Selection Commission (OSSC) released the OSSC JEO and JA Answer Key 2024 on 17th December 2024. Preliminary Examination of Junior Enforcement Officer and Junior Accountant-2023 (Advt. No. 5130/OSSC. Candidates who appeared for OSSC JEO and JA Computer Based Recruitment Examination can check their answer key by providing the login details i.e. Roll Number and Date of Birth. The direct link to check the official portal of OSSC Answer Key is also given in the article.

OSSC JEO & JA Answer Key 2024 Released

Through the recruitment drive, OSSC aims to fill a total of 31 vacancies for Junior Enforcement Officers (JEO) and Junior Accountant (JA) posts under the Comptroller, Legal Metrology, FS & CW Department of the Government of Odisha. Candidates who have any objection on the provisional answer key can submit their objection from the official website of OSSC using their roll number and date of birth.

OSSC JEO & JA Answer Key 2024 Link

The answer key link for the preliminary examination of Junior Enforcement Officer and Junior Accountant-2023 examination has been released on 17 December 2024 at https://www.ossc.gov.in. Answer key PDF link is also given here for the reference of the candidates. With the help of OSSC JEO & JA Answer Key 2024, candidates can check their responses and assess their performance in the preliminary exam.

Steps to download OSSC JEO & JA Answer Key 2024

  • Open a web browser and visit the official website of Odisha Staff Selection Commission (OSSC) https://www.ossc.gov.in.
  • On the home page, find and click on the link that reads, “Link for inviting objections to the provisional answer key of the preliminary examination of Junior Enforcement Officer and Junior Accountant-2023”.
  • Candidates are redirected to a new page where candidates are required to enter the login details Roll Number and Date of Birth.
  • Fill the captcha code and click on the login tab.
  • OSSC JEO & JA Answer Key PDF with correct responses will appear on the screen.
  • Download the answer key for future reference.

Rate this post
WhatsApp Group Join Now
Telegram Group Join Now

Hello friends, I am Ashok Nayak, the Author & Founder of this website blog, I have completed my post-graduation (M.sc mathematics) in 2022 from Madhya Pradesh. I enjoy learning and teaching things related to new education and technology. I request you to keep supporting us like this and we will keep providing new information for you. #We Support DIGITAL INDIA.

Sharing Is Caring:

Leave a Comment